Question

ram moves in east direction at a speed of 6 m/s and shyam moves 30 degree east of north at a speed of 6 m/s then find magnitude of their relative velocity .

Answer 1

Shyam moves 30° east of North so the angle between them is 60°,

Then,

Vrs=√Vr^2+Vs^2-2 (Vr)(Vs)COS60

      =√6^2+6^2-2(6)(6)(1/2)

      =√36+36-36

      =√36

      =6m/s

Answer 2

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$vr + vrs = vs$


$vrs = \sqrt[]{ {vs}^{2} + {vr}^{2} - 2vs \: vr \cos(60) }$


$= \sqrt[]{36 + 36 - 36} = \frac{6m}{s}$


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