Math, asked by Anonymous, 4 months ago

Ram saved Rs 5 in the first week of a year and then increased her weekly saving by Rs 1.75. If in the nth week, fher weekly savings become Rs 20.75, find n.

★Class :- 10th

Answers

Answered by Anonymous

Question :-

Ram saved Rs 5 in the first week of a year and then increased her weekly saving by Rs 1.75. If in the nth week, her weekly savings become Rs 20.75, find n.

Answer :-

Here, we have first saving i.e. first term as 5, then we have common difference of Rs. 1.75 and then we have last term as 20.75.

First term, a = 5
Common difference, d = 1.75
Nth term of AP, aₙ = 20.75

⇒ aₙ = a + ( n - 1 ) d

⇒ 20.75 = 5 + ( n - 1 ) 1.75

⇒ 20.75 - 5 = 1.75 ( n - 1 )

⇒ 15.75 = 1.75 ( n - 1 )

⇒ n - 1 = 9

⇒ n = 10

Value of n = 10 weeks

Answered by khushiangel1

here is your answer

Saving made in first week= 5Saving made in second week = 5+1.75 = 6.75Saving made in third week = 6.75 +1.75= 8.50So , the series is 5, 6.75 ,8.50Since difference is same , it an Ap d = 1.5Given, nth week , her savings become Rs. 20.75 so an= 20.75a= 5. , d= 1.75we need to find n

Saving made in first week= 5Saving made in second week = 5+1.75 = 6.75Saving made in third week = 6.75 +1.75= 8.50So , the series is 5, 6.75 ,8.50Since difference is same , it an Ap d = 1.5Given, nth week , her savings become Rs. 20.75 so an= 20.75a= 5. , d= 1.75we need to find n an=. a+ ( n-1 ) d

9= n-1

9= n-110=n

9= n-110=n hence , in 10th week her savings become 20.75

Hope it's helpful for you thank you ☺️

Previous Question

Next Question

Ram saved Rs 5 in the first week of a year and then increased her weekly saving by Rs 1.75. If in the nth week, fher weekly savings become Rs 20.75, find n.★Class :- 10th​