Ramakanth repays a loan of rs. 6500 by paying rs. 40 in the first month and then increasing the payment by rs. 30 every month. In how many months will he be able to clear the loan. Arithmetic progression sum
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20 months ... Arithmetic sequences are the sequences which have a constant ... In other words, it is the sequence of numbers in which we obtain the next ... And then, increases it by 15 every month thereafter. ... Where, Sn is the sum of n number of terms. a is the first term( 20 ). ... →n(40+15n−15)=2×3250
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