Raman deposits a certain sum of money each month is a recurring deposit account of a bank if the rate of interest is 9 whole 1/2% per annum and Raman gets 78,638 from the bank after 3 whole 1/2% years find the value of monthly installment
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Answer:
1600
Step-by-step explanation:
Given, r = 9 1/2% p.a. = 9.5%
A = ₹ 78638
n = 3 1/2 years = 42 months
Let Monthly Installment be P
∵ A = Pn + (P*n(n+1)*r)/2400
⇒ 78638 = P * 42 + (P * 42 * 43 * 9.5)/2400
⇒ 78638 = 42P + (P * 42 * 43 * 19/2)/2400
⇒ 78638 = 42P + (P * 21 * 43 * 19)/2400
⇒ 78638 = 42P + (P * 7 * 43 * 19)/800 (Dividing 21 and 2400 by 3)
⇒ 78638 * 800 = 800(42P + 5719P/800) (Multiplying both sides by 800)
⇒ 78638 * 800 = 33600P + 5719P
⇒ 78638 * 800 = 39319P
⇒ P = 78638 * 800 / 39319 = ₹ 1600
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