Question

Ramesh and Mahesh solve an equation. In solving Ramesh commits a call mistake in the constant term and finds the roots 8 and 2 Mahesh commits a mistake in the coefficient of X and find the root -9 and -1. The correct roots are

Answer 1

Let the correct equation be ax²+bx+c

Since roots found by Ramesh are 8 and 2
( x - 8 ) * ( x - 2 ) = x² - 10x + 16
And because he made a mistake in constant term so the values of a = 1 , b = -10

Since roots found by Mahesh are -9 and -1
( x + 9 ) * ( x + 1 ) = x² + 10x + 9
And because he made a mistake in coefficient of X so the values of a = 1 , c = 9

Hence now according to the values of a , b & c,
The correct equation becomes :
x² - 10x + 9
Now the roots of the correct equation are :
9 and 1.

Answer 2

Answer:

Step-by-step explanation:

Let the correct equation be ax²+bx+c

Since roots found by Ramesh are 8 and 2

( x - 8 ) * ( x - 2 ) = x² - 10x + 16

And because he made a mistake in constant term so the values of a = 1 , b = -10

Since roots found by Mahesh are -9 and -1

( x + 9 ) * ( x + 1 ) = x² + 10x + 9

And because he made a mistake in coefficient of X so the values of a = 1 , c = 9

Hence now according to the values of a , b & c,

The correct equation becomes :

x² - 10x + 9

Now the roots of the correct equation are :

9 and 1.