Math, asked by sudhakar3211, 11 months ago

Ramesh and Suresh 20 years and 12 year old respectively find how many years ago the age of the Ramesh was twice that of a Suraj​

Answers

Answered by AJRules8008
8

Answer:

Plz mark as brainliest

Your answer is 3 years ago .

Because when Suresh was 9 years old Ramesh was 18 years old.

So ,

( Suresh's age) × 2 = ( Ramesh's age)

Therefore,

9 × 2 = 18

Answer : 3 years ago

Plz mark as brainliest

Answered by niladripramanick9
33

Answer:

we know ,

- present age of Ramesh is 20

- present age of suresh is 12

we also know the time gap remains the same for both so ,

-lets take the time gap as "x"

20 - x = 2(12 - x)

{as the age of Ramesh "x" years ago was 2times of suresh's age "x" years ago .

= solving the equation we get.

24 - 20 = 2x -x

= x= 4.

... therefore 4years ago Ramesh's age was twice of Suresh.

i,e. Ramesh age = 16

Suresh age = 8.

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