Question

Ramesh is twice as good a workman as suresh and finishes a piece of work in 3 hours less than suresh. In how many hours they together could finish that piece of work

Answer 1

Answer:

Ramesh and Suresh together could finish piece of work in 2 hours

Step-by-step explanation:

Given that Ramesh is twice as good a workman as Suresh.

Let Ramesh completes work in $x$ hours

Thus, Suresh complete work in $2x$ hours

Also, given that Ramesh finishes a work in 3 hours less than Suresh

Thus, we have

$2x - x = 3\\\\x = 3$

Ramesh can finish work in $3 \hspace{0.1cm}hours$

Suresh can finish work in $2 \times 3 = 6\hspace{0.1cm}hours$

Now, Ramesh's 1 hour work $=\frac{1}{3}$

And, Suresh's 1 hour work $=\frac{1}{6}$

Total work is LCM of (3, 6) $=6\hspace{0.1cm}parts$

Ramesh's 1 hour work $=\frac{6}{3}=2\hspace{0.1cm}parts$

And, Suresh's 1 hour work $=\frac{6}{6}=1\hspace{0.1cm}part$

(Ramesh + Suresh)'s 1 hour work $= (\,2 + 1)\, = 3\hspace{0.1cm}parts$

Thus, 3 parts of work completed in 1 hour

6 parts of work completed in $\frac{6}{3} = 2\hspace{0.1cm}hours$

Hence, Ramesh and Suresh together could finish piece of work in 2 hours