Ramesh took two beakers A and B containing hot water and cold water respectively. In each beaker he dropped a crystal of copper sulphate.He kept the beakers undisturbed .After sometime what did he observe ? Why ?
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He must have observed that the crystal of copper sulphate in beaker A has diffused evenly than in beaker B. This describes the phenomenon of diffusion. On heating, diffusion becomes faster because the kinetic energy increases. So the particles of CuSO4(copper sulphate) must have diffused with the particles of hot water quickly than in the cold water.
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Explanation:
The given compound is copper sulfate and it is an ionic compound as it is formed by transfer of electrons from copper to sulfate atoms.
Since, beaker A contains hot water so when we add a crystal of copper sulfate in it then it will readily dissociate into ions. Due to this rate of formation of ions will be faster.
On the other hand, beaker B contains cold water so when we add a crystal of copper sulfate in it then it will take time to dissociate as water is cold.
Due to this rate f formation of ions will not be fast enough.
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