Question

ramu bought 5 kg of sugar and 5 kg of jaggery for 400 rupees. One kg of jaggery costs 12 rupees more than one kg pf sugar . What is the price of each per kg​

Answer 1

Step-by-step explanation:

1 kg of sugar = x

1kg of jaggary= x+12

prize of 5 kg of jaggery =400

prize of 5kg of sugar =400

prize of 1 kg of sugar =400/5

= ₹80

1 kg of jaggery =x+12,where x is the prize of 1 kg of pf sugar

so, x=80

x+12 = rate of 1 kg of jaggery

80+12

₹92 is the prize of jaggery per kg

Answer 2

Step-by-step explanation:

price of 5kg jaggery and 5kg sugar = 400 rs

1 kg sugar price = X

1 kg of jaggery price = X +12

so, total price of 5 kg sugar and 5 kg jaggery =

= 5 × (X + X + 12)

400 = 5X + 5 X + 5 × 12

400 = 5 X + 5 X + 60

400 - 60 = 10 X

340 = 10 X

340÷ 10 = X

34= X

so, 1 kg sugar price , X = 34

(so, 5 kg sugar = 34× 5

= 170)

1 kg of jaggery price = X + 12

=34+12

=46

( so, 5 kg of jaggery price = 46 × 5

= 230

total = 170 + 230 = 400)