Question

range is 87.58 m assuming maximum range find the initial velocity with which neeraj chopra threw javelin

Answer 1

Answer:

2. $r = u { }^{2} sin2 \alpha \div g$
3. for max range
4. $\alpha = 45$so now
5. $u = \sqrt{rg}$
6. u=29.3 m/s