Range of f(x)=4^x+2^x+1 is?
MrsJUNGKOOK:
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Answer:
Step-by-step explanation:
4^x + 2^x + 1 = (2^x)^2 + 2^x + 1
= (2^x + 1 / 2)^2 + 3 / 4 >= 3 / 4 for all x.
thus Range = [3 / 4 , infinity)
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Ans is [3/4, infinity). Hope this will help you.
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