Question

If the centre of a circle is (-6,8) and it passes through the origin, then equation to its tangent at the origin is

Answer 1

The slope of the line joining the origin to the center is −86

A tangent is perpendicular to the radius at the point of contact, so it’s slope will be 68=34 (because for perpendicular lines, product of slopes is = −1)

And, the line satisfies the origin, so there’s no constant term (recall y=mx+c, where c is the y-intercept. Here, it’s zero)

Hence, the required equation : y=3x4

Answer 2

Answer:

4y=3x(correct ans)

Step-by-step explanation:

y=mx+c

m=(X-X1/Y-Y1)=6/8=3/4

y=3/4(x)+0

4y=3x