Math, asked by harshith8143, 23 hours ago

Range of f(x) = sin log x-√1+x²​

Answers

Answered by fathimaatiqbaig
0

Step-by-step explanation:

Correct option is

A

an even function

f(x)=sin(log(x+x2+1))

⟹f(−x)=sin(log(−x+(−x)2+1))

⟹f(−x)=sin(log(x2+1−x))

⟹f(−x)=sin(log((x2+1−x)×x2+1+xx2+1+x))

⟹f(−x)=sin(logx2+1+x1)

⟹f(−x)=−sin(log(x+x2+1))

⟹f(−x)=−f(x)

Hence, f(x) is an odd function.

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