rani and sneha working separately can finish a job in 8 hour and 12 hour respectively if they work for an hour alternately ,Rani beginning at 9 :00 am when will the job be finished
Answers
Answered by
5
Answer:
Work done by Ganga in 1 hour =
1
8
Work done by Saraswati in 1 hour =
1
12
They are working alternatively with Ganga beginning the job.
Work done in every two hours =
1
8
+
1
12
=
5
24
Work done in 4×2=8 hours =
5
×
4
24
=
5
6
Remaining work =
1
−
5
6
=
1
6
In 9th hour, Ganga starts the work and does
1
8
of the work
Work remaining =
1
6
−
1
8
=
1
24
In 10th hour, Saraswati starts the work
Time needed to finish the remaining work
=
(
1
24
)
(
1
12
)
=
1
24
×
12
= 0.5 hour= 30 minutes
i.e., work will be completed in 9 hour 30 minutes, after 9 am
i.e., at 6:30 pm
Answered by
0
Answer:
1/8+1/12=5/24 full work 1×48/5 8 hour +1hour =9hour s sneak do remaining work in 30 minutes Time 9+9 h and 30 minute =18h and 30 minute ANS Rani finished the job in 6:30pm
Similar questions