Question

Ranjit 13 years younger than Lalit. Soman is 4 years younger than Ranjit Santosh age is equal to the sum of the ages of Ranjit and Soman. If the total age of all of them together is 45, find their ages

Answer 1

Let Ranjits's age be x

then

Ranjit=x

Lalit=13+x

Soman= x-4

Santosh= x+(x-4)

x+13+x+x-4+x+x-4=45

5x=45-13+4+4

5x= 40

x=40/5

x=8

Hence Ranjit =8 years

Lalit=21 years

Soman= 4 years

Santosh=8+4= 12 years\

Hope it helps

Answer 2

Answer:

$\large\boxed{\sf{21, 12, 8 \; and \; 4 \; yrs. }}$

Step-by-step explanation:

Let us assume that

• Age of Ranjit = x yrs.
• Age of Soman = y yrs.
• Age of Santosh = z yrs.
• Age of Lalit = w yrs.

According to question :

Ranjit is 13 yrs. younger than Lalit

=> x = w - 13

Soman is 4 yrs. younger than Ranjit.

=> y = x - 4

Santosh age equals sum of Ranjit and Soman

=> z = x + y

Also, total sum of ages = 45

=> x + y + z + w = 45

=> w - 13 + x - 4 + x + y + w = 45

=> 2w + 2x + y = 45 + 17

=> 2w + 2x + x - 4 = 62

=> 2w + 3x = 66

=> 2w + 3(w - 13) = 66

=> 5w = 66 + 39

=> w = 105/5

=> w = 21 yrs.

=> x = 21 - 13

=> x = 8 yrs.

=> y = 8 - 4

=> y = 4 yrs.

=> z = 8 + 4

=> z = 12 yrs.

Hence,

• Age of Ranjit = 8 yrs.
• Age of Soman = 4 yrs.
• Age of Santosh = 12 yrs.
• Age of Lalit = 21 yrs.