Question

Ranjit give a shopkeeper hundred Rupees by 3 notebooks the shopkeeper gives him three notbook and returned 22 rupees if the price of each notebook is RS.×,then make a correct equation for the solution​

Answer 1

Answer:

Given that Rakesh purchased at least 11 items of each

Let the number of pens, erasers, and sharpeners be (11+p),(11+e), and (11+s) respectively, such that-

(i) s>e>p (Given)

(ii) s,e,p∈I+

Rakesh went to a stationary shop to purchase a total of 38 pens, eraser, and sharpeners.

∴(11+p)+(11+e)+(11+s)=38

⇒p+e+s+33=38

⇒p+e+s=5

0,2 and 3 are the only unequal positive integral values which results 5 on addition.

∵s>e>p

∴p=0,e=2,s=3

Hence, no. of pens Rakesh purchased =11+0=11

no. of erasers Rakesh purchased =11+2=13

no. of sharpners Rakesh purchased =11+3=14

Given that If each pen cost Rs. 2 each eraser cost Rs. 3 and each sharpener cost Rs. 4.

∴ total expenditure=11×2+13×3+14×4=22+39+56=Rs.117

The minimum expenditure be could have incurred on the items = Rs. 117