Question

Ranjith throws a dice find the probability of getting:a) an even number b) odd number c)number less than 4 d) prime number.​

Answer 1

Answer:

a) possible outcomes = 2 , 4 , 6

PROBABILITY =

$\frac{3}{6} = \frac{1}{2}$

b) possible outcomes = 1 , 3 , 5

PROBABILITY =

$\frac{3}{6} = \frac{1}{2}$

c) possible outcomes = 1 , 2 , 3

PROBABILITY =

$\frac{3}{6} = \frac{1}{2}$

d) possible outcomes = 2 , 3 , 5

PROBABILITY =

$\frac{3}{6} = \frac{1}{2}$

hope it helps...

Answer 2

$(a)possible \: outcomes = 2,4,6$

$\\probability = \frac{3}{6} = \frac{1}{2}$

$(b)possible \: outcomes = 1,3,5$

$\\probability = \frac{3}{6} = \frac{1}{2}$

$(c)possible \: outcomes = 1,2,3$

$\\probability = \frac{3}{6} = \frac{1}{2}$

$(d)possible \: outcomes = 2,3,5$

$\\probability = \frac{3}{6} = \frac{1}{2}$