Rashid is 20 year older than zahid. One third of rashid's age equals half of Zahid's. Find their ages
Answers
Answered by
3
let zahids age be x yrs then rashids age will be 20+x
a/q 1/3(20+x)=x/2
on solving we get x=40
hence zahid is 40 yrs old and rashid is 40+20= 60 yrs old
a/q 1/3(20+x)=x/2
on solving we get x=40
hence zahid is 40 yrs old and rashid is 40+20= 60 yrs old
aarijkhan63:
Thank u
Answered by
5
Let the age of Rashid be x and Zahid be y.
Acc.to the 1st condition;
x-20=y
therfore
x-y=20---(i)
Acc. to the 2nd condition;
1/3x=1/2y
therefore
2x=3y
2x-3y=0----(ii)
Multiplying (i) by 2;
2x-2y=40---(iii)
Subtracting (ii) from (iii);
2x-2y=40
2x-3y=0
(-) (+) (-)
--------------
y=40
Substituting the value of y in (1)
x-y=20
x-40=20
x=60
Therefore the age of Rashid is 60 years
and the age of zahid is 40 years.
hope i helped u:)
Acc.to the 1st condition;
x-20=y
therfore
x-y=20---(i)
Acc. to the 2nd condition;
1/3x=1/2y
therefore
2x=3y
2x-3y=0----(ii)
Multiplying (i) by 2;
2x-2y=40---(iii)
Subtracting (ii) from (iii);
2x-2y=40
2x-3y=0
(-) (+) (-)
--------------
y=40
Substituting the value of y in (1)
x-y=20
x-40=20
x=60
Therefore the age of Rashid is 60 years
and the age of zahid is 40 years.
hope i helped u:)
Similar questions