Question

rate constants of reaction of a reaction is 10-3 what will relations between t9/10 and t/2​

Answer 1

Answer:

Rate  constant k=1×10−3mol/lit.min

A→2B

 After 100 minutes,

reactant used=k×100

=0.1mole/litersA:B=1:2

∴ Product formed=2× reactants used

=0.1×2

=0.2mol/L