Question

rate law of a reaction is rate=k(NO)^2(O2). By how many times does the rate of the reaction increase if the volume of the reaction vessel is halved​

Answer 1

Heya,

The order of reaction is 2 + 1 = 3.

By decreasing the volume to half, the concentration becomes double.

Hence, the rate of reaction becomes (2)³ = 8 times

Regards

Kshitij