rate law of a reaction is rate=k(NO)^2(O2). By how many times does the rate of the reaction increase if the volume of the reaction vessel is halved
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Heya,
The order of reaction is 2 + 1 = 3.
By decreasing the volume to half, the concentration becomes double.
Hence, the rate of reaction becomes (2)³ = 8 times
Regards
Kshitij
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