Question

Rate of a reaction doubles or triples when temperature is increased by 10°C for the following reactions
a) 2NO+02 → 2N02
b) 2H2,02 → 2H2 0+02
c) 2H2+02, +2H2,0
d) Caco3, CaO+CO2​

Answer 1

Answer:

..........................

Explanation:

.........................

Answer 2

Answer:

It is given that T

1

= 298 K

∴T

2

= (298 + 10) K

= 308 K

We also know that the rate of reaction doubles when the temperature is increased by 10 K.

Therefore, let us take the value of k1 = k and that of k2 = 2k

Also, R = 8.314 J K - 1 mol - 1

Now, substituting these values in the equation:

log

k

1

k

2

=

2.303×R

E

a

(

T

1

1

−

T

2

1

)

log

1

2

=

2.303×8.314

E

a

(

298

1

−

308

1

)

E

a

=52.9kJ mol

−1

Explanation:

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