Question

Rate Of Adsorption Of And On 1 Gram Of Activated Charcoal Is Minimum For ______

Answer 1

Explanation:

The surface area of 25 g of charcoal is 25×1000=25000m

2

Surface area occupied by one ammonia molecule =0.3×0.3=0.09nm

2

=9×10

−20

m

2

Total number of ammonia molecules =

9×10

−20

25000

=2.77×10

23

The number of moles of ammonia =

6.023×10

23

2.77×10

23

=0.46

Volume of ammonia adsorbed 22.4×0.46=10.3L