Rate of appearance of O2 = 9.6g/sec.Calculate rate of Dissociation of H2O2 in g/sec.
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2H2O2 → 2H2O + O2
here we see 2 mole of H2O2 react to form 1 mole of O2 .
it means
rate of decrement of H2O2 is 2 times of rate of increment of O2 .
its also mean ,
34g of H2O2 completely decompose and form 32g O2.
now, according to kinetic theory .
1/2 × d[ H2O2]/dt = d[O2]/dt
1/2 × d[ H2O2]/dt = 9.6/32
d[ H2O2]/dt = 19.2/32 conc/sec
d[H2O2]/dt = 19.2/32 × 34g/sec
d[ H2O]/dt = 19.2×34/32
= 19.2 × 17/16 g/sec
= 1.2 × 17= 20.4 g /sec
here we see 2 mole of H2O2 react to form 1 mole of O2 .
it means
rate of decrement of H2O2 is 2 times of rate of increment of O2 .
its also mean ,
34g of H2O2 completely decompose and form 32g O2.
now, according to kinetic theory .
1/2 × d[ H2O2]/dt = d[O2]/dt
1/2 × d[ H2O2]/dt = 9.6/32
d[ H2O2]/dt = 19.2/32 conc/sec
d[H2O2]/dt = 19.2/32 × 34g/sec
d[ H2O]/dt = 19.2×34/32
= 19.2 × 17/16 g/sec
= 1.2 × 17= 20.4 g /sec
abhi178:
now , i hope this will correct shati
Correct and exact answer is 20.4
Just made a correction in Molecular mass of H2O2 that is 34!!
:-)
yeah !!! now i am perfect no chance to edit qgain and again xD
sorry , for again and again edit
xD , xD , xD
yeah! xD......absolutely correct answer!! Keep it up!! :)
thanks for helping me!
xD
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