Question

Rate of heat flow through a cylindrical rod is Qą.
Temperatures of ends of rod are T, and T... If all the
linear dimensions of the rod become double and
temperature difference remains same, it's rate of
heat flow is Q2, then:
(1) Q, = 2Q,
(2) Q, = 2Q,
(3) Q2 = 407
(4) Q, = 4Q​

Answer 1

Answer:

(4)

Explanation:

is the answer

thanks for the points