Question

rate of interest 4percent time period 3years simple interest 120 find principal&amount​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Principal=1500\:rupees}}$

${\bold{\therefore Amount=1620\:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Rate = 4 \% \\ \\ \implies Simple \: Interest = 120 \: rupees \\ \\ \implies Time = 3 \: years \\ \\ \underline \bold{To \: Find: } \\ \implies Principal = ? \\ \\ \implies Amount = ?$

•. According to given question :

$\bold{ Using \: formula \:of \: si : } \\ \implies S.I = \frac{P\times R\times T}{100} \\ \\ \bold{Putting \: given \: values : } \\ \implies 120 = \frac{P \times 4\times 2}{100} \\ \\ \implies 120 \times 100 = 8p \\ \\ \implies P= \frac{12000}{8} \\ \\ \bold{\implies P= 1500 \: rupees} \\ \\ \bold{For \: Amount : } \\ \implies A = S.I + P \\ \\ \implies A = 120 + 1500 \\ \\ \bold{\implies A = 1620 \: rupees}$

Answer 2

Answer:

$\huge\sf\color{green}{Principle:- 1500.}$

$\huge\sf\color{green}{Amount:-1620.}$

Given that :-

• Rate of interest = 4%

• Time period = 3 years.

• Simple interest = 120

To find :-

• Principle = ?

• Amount = ?

$\huge\mathfrak{Solution:-}$

Principle:-

= Formula of Simple Interest.

$si = \frac{p \times r \times t}{100}$

Putting the given values :-

$120 = \frac{p \times 4 \times 2}{100} \\ \\ 120 \times 100 = 8p \\ \\ p = \frac{12000}{8} \\ \\ p = 1500 \: rate$

Amount :-

$a = simple \: interet + principle \\ \\ a = 120 + 1500 \\ \\ a = 1620 \: rupees \: or \: amount$

$\boxed{Principle:-1500}$

$\boxed{Amount:-1620}$