Question

ratianlise the denominator and simplify 1/7-root 5​

Answer 1

Heres your answer :-

$= > \frac{1}{7 - \sqrt{5} } \times \frac{ 7 + \sqrt{5} }{7 + \sqrt{5} }$

use the identity :)

$(x + y)(x - y) = x ^{2} - y ^{2}$

Lets solve •_•

$= > \frac{7 + \sqrt{5} }{7 ^{2} - ( \sqrt{5}) ^{2} }$

$= > \frac{7 + { \sqrt{5} } }{49 - 5}$

$= > \frac{7 + \sqrt{5} }{44}$

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Answer 2

Step-by-step explanation:

1/7-√5

=1 / 7-√5 × 7+√5 / 7+√5

=7+√5 / (7)^2 - (√5)^2

= 7+√5 / 49 - 5

=7+√5 / 44