Ratinalise the denominator
3/4-√7
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There are multiple ways to go about doing this. The first method that I thought of is to start by looking at the fraction like so:
3–√−2(2+3–√)−7–√
From this, it makes sense to try multiplying the numerator and the denominator by (2+3–√)+7–√ , giving
3–√−2(2+3–√)−7–√×(2+3–√)+7–√(2+3–√)+7–√=23–√+3+21−−√−4−23–√−27–√(2+3–√)2−7=−1−27–√+21−−√43–√.
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