ratinalize 4/2+root 3 +root 7
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Hi ,
4/( 2 + √3 + √7 )
= [4(2+√3-√7 )]/[(2+√3+√7)(2+√3-√7)]
= [4(2+√3-√7)]/[( 2+√3)² - ( √7 )² ]
= [ 4(2+√3-√7)]/( 4 + 3 + 4√3 - 7 )
= [ 4(2+√3-√7) ] / ( 4√3 )
= ( 2 + √3 - √7 ) / √3
= [ √3( 2 + √3 - √7 ) ]/( √3 × √3 )
= ( 2√3 + 3 - √21 ) / 3
I hope this helps you.
: )
4/( 2 + √3 + √7 )
= [4(2+√3-√7 )]/[(2+√3+√7)(2+√3-√7)]
= [4(2+√3-√7)]/[( 2+√3)² - ( √7 )² ]
= [ 4(2+√3-√7)]/( 4 + 3 + 4√3 - 7 )
= [ 4(2+√3-√7) ] / ( 4√3 )
= ( 2 + √3 - √7 ) / √3
= [ √3( 2 + √3 - √7 ) ]/( √3 × √3 )
= ( 2√3 + 3 - √21 ) / 3
I hope this helps you.
: )
0O9I8U7Y6T:
is this is correct answer ..
thanks
brother's
is this is helpfull for me
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