Question

Ratio in which the line 3x+4y =7 divide the line segment joining the point (1,2) & (-2,1)

Answer 1

This is your answer of

CORDINATE GEOMETRY

Answer 2

The ratio is 4:9

Step-by-step explanation:

Consider the provided information.

We need to find the ratio in which the line 3x+4y =7 divide the line segment joining the point (1,2) & (-2,1).

By section formula if a point divides the line segment in a ratio then the coordinate of points is $(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})$  where m and n are the ratio.

$(\frac{m(-2)+n(1)}{m+n},\frac{m(1)+n(2)}{m+n})$

$(\frac{-2m+n}{m+n},\frac{m+2n}{m+n})$

Substitute the value of x and y in provided equation of line.

$3(\frac{-2m+n}{m+n})+4(\frac{m+2n}{m+n}) =7$

$3(-2m+n)+4(m+2n)=7(m+n)$

$-6m+3n+4m+8n=7m+7n\\-2m+11n=7m+7n\\9m=4n\\m:n=4:9$

Hence, the ratio is 4:9

#Learn more

The line segment joining the points (1,2) and (k,1) is divided by the line 3x+4y-7=0 in the ratio 4:9 then k is

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