Ratio of 13.6 kg is to 1, 020 g
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Given : AB = AC and D, E and F are mid points in BC, AB and AC respectively.
To Prove : AD is perpendicular to EF and is bisected by it
To construct : Join DE and DF.
Proof : Since EF are formed by joing mid points of triangle then EF || BC.
And since parallel lines are at 90° angle hence AD is perpendicular to EF.
Now, DF || AB and DF = 1 AB / 2
Since 1 AB / 2 = BE
DF = BE
Now, AB = AC
1 AB / 2 = 1 AC / 2
BE = AF
DF = AF
Now, taking triangle AOF and DOF.
DF = AF ( Proved above )
OF = OF ( Common )
angle AOF = ange DOF ( 90° each )
Hence triangle AOF ~ DOF by RHS congruency. Thus, AO = OD.
Hence EF bisect AD.
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13
1kg=1000g
13.6kg=1000×13.6
=1360
1360:1020
680:510
340:255
68:51
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