Question

Ratio of energy of photon of wave length 3000A° and 8000A° is

Answer 1

As we know that
E = hc/ lemda
Here lemda is the wavelength.

E1 = hc / lemda 1
E2 = hc/ lemda 2

E1/E2 = lemda 2 / lemda 1

E1/E2 = 8/3

Hope you get your answer.

Answer 2

Answer:

Ratio of energy of photon of wave length 3000 A° and 8000 A° is 8 : 3.

Explanation:

$E=\frac{h\times c}{\lambda}$

where,

E = energy of photon = ?

h = Planck's constant = $6.63\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

1) $\lambda$ = wavelength = $3000\AA=3000\times 10^{-10}m$

Now put all the given values in the above formula, we get the energy of the photons.

$E=\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{3000\times 10^{-10}m}$

2) $\lambda '$ = wavelength = $8000\AA=3000\times 10^{-10}m$

Now put all the given values in the above formula, we get the energy of the photons.

$E'=\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{8000\times 10^{-10}m}$

Ratio of energies of wavelengths :

$\frac{E}{E'}=\frac{8}{3}=2.6666$