ratio of number of moelecules of 71 g of gasous chlorine to no of molecules of 2g of hydrogen
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Answer:
2 : 1
Explanation:
Number of molecules (n) = Given mass / molecular mass
Number of molecules of Chlorine (C)= 71g / 35g
= 2
Number of molecules of Hydrogen (H)= 2g / 2g
= 1
Therefore,
ratio = 2 : 1
Hope this is clear to you !!
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