Chemistry, asked by arifareej388, 4 months ago

ratio of number of moelecules of 71 g of gasous chlorine to no of molecules of 2g of hydrogen​

Answers

Answered by chanchalt521
0

Answer:

2 : 1

Explanation:

Number of molecules (n) = Given mass / molecular mass

Number of molecules of Chlorine (C)= 71g / 35g

= 2

Number of molecules of Hydrogen (H)= 2g / 2g

= 1

Therefore,

ratio = 2 : 1

Hope this is clear to you !!

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