ratio of radii of oxygen to deutron nuclie is
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Answer:
∵R=R
o
(A)
1/3
where R
o
is constant and A is mass number
For
8
O
16
=2.8×10
−15
=R
o
×(16)
1/3
R
o
=
2.51
2.8×10
−15
=1.11×10
−15
m
For
82
Pb
207
⇒R=R
o
(A)
1/3
=R=1.11×10
−15
×(207)
1/3
=6.56×10
−15
m
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