Ratio of radius two soap bubbles is 2:1 then the ratio of their excesa pressure is
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Satwinder04:
Option to ya ha 1)2:1 (2) 4:1 (3) 1:4 (4) 1:2
so i got 1:2 see
so answer ia (4)
Ok tq
Answered by
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heya...........
Given :
Let R1 and R2 be the radii of two soap bubbles
R1/R2=2/1
let σ be the surface tension of soap bubble.
Excess pressure inside bubble with radius R1=P1=4σ/R1
Excess pressure inside bubble with radius R2=P2=4σ/R2
P1/P2=[4σ/R1 ]xR2/4σ
=R2/R1
p1/p2=1/2
..tysm................@kundan
Given :
Let R1 and R2 be the radii of two soap bubbles
R1/R2=2/1
let σ be the surface tension of soap bubble.
Excess pressure inside bubble with radius R1=P1=4σ/R1
Excess pressure inside bubble with radius R2=P2=4σ/R2
P1/P2=[4σ/R1 ]xR2/4σ
=R2/R1
p1/p2=1/2
..tysm................@kundan
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