Question

Ratio of rate of diffusion of H2 and O2 under identical condition of temp and pressure is

Answer 1

Answer:

option b 8:1 is the correct answer......mate

Answer 2

The answer would be option C) 4:1

Explanation:

According to Graham's law "the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molecular weight".

Mathematically, it can be written as:

$r_g =\sqrt{\frac{1}{M_g} }$

• When there are two gases, we can write the relation as:

$\frac{r_1}{r_2} =\sqrt{\frac{M_2}{M_1} }$

• In the given question, gas 1 is dihydrogen$(H_2)$ , and gas 2 is dioxygen$(O_2).$

Thus, the formula becomes

$\frac{r_H_2}{r_O_2} =\sqrt{\frac{M_O_2}{M_H_2} }$

• Now, the molar mass of $H_2 = 2 g/mol,$

and the molar mass of $O_2 = 32 g/mol,$

• Thus,

$\frac{r_H_2}{r_O_2} =\sqrt{\frac{32}{2} }$

$\frac{r_H_2}{r_O_2} =\sqrt{16}$

$\frac{r_H_2}{r_O_2} =4$

So, the ratio is 4:1