Ratio of the energy of electrons in 1st shell of he and 3rd shell of li+2 is
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Answer: 4:1
Explanation:
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Given :
Energy of electrons in 1st shell of He and 3rd shell of
To Find :
Ratio of the energy of electrons in 1st shell of He and 3rd shell of
Solution :
We know, Energy of an electron in nth orbit = - ×13.6 eV
(where Z = atomic number ; n = Shell number)
For Helium, Z = 2 and n = 1 (as given)
Energy of electron in the First shell of He (E) = × 13.6 eV
= 4 × 13.6 eV
For , Z = 3 and n = 3 (as given)
Energy of electron in the third shell of (E) = × 13.6
= 13.6 eV
Ratio of E to E = =
∴ The ratio of the energy of electrons in 1st shell of He and 3rd shell of is 4 : 1
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