Question

Ratio of three sides of a triangles is 2:5:7. The perimeter of the triangles is 98cm. Find the sides of the triangle​

Answer 1

Given :

• Ratio of three sides of a Triangle is 2:5:7.
• Perimeter of triangle is 98 cm .

To Find :

• Sides of the triangle .

Solution :

$\longmapsto\tt{Let\:first\:side\:be=2x}$

$\longmapsto\tt{Let\:second\:side\:be=5x}$

$\longmapsto\tt{Let\:third\:side\:be=7x}$

A.T.Q :

$\longmapsto\tt{2x+5x+7x=98}$

$\longmapsto\tt{14x=98}$

$\longmapsto\tt{x=\cancel\dfrac{98}{14}}$

$\longmapsto\tt\bf{x=7}$

Value of x is 7 .

Therefore :

$\longmapsto\tt{Length\:of\:first\:side=2(7)}$

$\longmapsto\tt\bf{14\:cm}$

$\longmapsto\tt{Length\:of\:second\:side=5(7)}$

$\longmapsto\tt\bf{35\:cm}$

$\longmapsto\tt{Length\:of\:third\:side=7(7)}$

$\longmapsto\tt\bf{49\:cm}$

Answer 2

$\quad\bullet\:\small\boxed{\sf{\green{Sides\:of\:triangle = 14\:units\:,\:35\:units\:and\:49\:units}}}$

$\underline{\red{\bigstar}{\underline{\bf{Given}}}\red{\bigstar}}$

• Ratio of three sides of a triangle is 2:5:7
• Perimeter of a triangle is 98 cm

$\underline{\red{\bigstar}{\underline{\bf{To\:Find}}}\red{\bigstar}}$

• Sides of a triangle

$\underline{\red{\bigstar}{\underline{\bf{Solution}}}\red{\bigstar}}$

ㅤㅤ» Let :-

• First side be 2s
• Second side be 5s
• Third side be 7s

ㅤㅤㅤㅤㅤㅤ━━━━━━━━━━

$\qquad:\implies\quad\sf Perimeter_{(Triangle)} = Sum\: of \:it's \:sides$

★ Putting all known values :-

$\qquad:\implies\quad\sf 98 = 2s + 5s + 7s$

$\qquad:\implies\quad\sf 98 = 14s$

$\qquad:\implies\quad\sf \dfrac{98}{14} = s$

$\qquad:\implies\quad\sf \dfrac{\cancel{98}}{\cancel{14}} = s$

$\qquad:\implies\quad{\boxed{\frak{\orange{s = 7\:units}}}}\:\blue{\bigstar}$

ㅤㅤㅤㅤㅤㅤ━━━━━━━━━━

Hence,

• First side = 2s = 2 × 7 = 14 units
• Second side = 5s = 5 × 7 = 35 units
• Third side = 7s = 7 × 7 = 49 units

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬