Question

Ratio of translatory kinetic energy and rotational kinetic energy in the motion of disc​

Answer 1

Answer:

The kinetic energy of translational motion of a rolling body ( here disc) is Kt= (1/2) mv^2 where v is linear velocity of center of mass of the body. The rotational kinetic energy is given by Er= (1/2) I w^2, where I is moment of inertia of the body about axis of rotation.

Answer 2

The kinetic energy of translational motion of a rolling body ( here disc) is Kt= (1/2) mv^2 where v is linear velocity of center of mass of the body. The rotational kinetic energy is given by Er= (1/2) I w^2, where I is moment of inertia of the body about axis of rotation.

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