Question

rationaise the denominator of 17+√3.​

Answer 1

Question :-

rationalise it

→ 17+√3

Answer :-

For rationalise -

$\to \: 17 + \sqrt{3} \: \: \: \bigg \{ \frac{17 - \sqrt{3} }{17 - \sqrt{3} } \bigg \} \\ \\ \to \: \frac{ {(17)}^{2} - {( \sqrt{3} )}^{2} }{17 - \sqrt{3} } \\ \\ \to \: \frac{289 - 3}{17 - \sqrt{3} } \\ \\ \to \: \frac{286}{17 - \sqrt{3} }$