Question

Rationalisation form of 1/root 9 - root 8

Answer 1

Answer :

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Answer 2

Answer:

$\frac{1}{ \sqrt{9} - \sqrt{8} } = \frac{1}{3 - 2\sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } = \frac{3 +2 \sqrt{2} }{ {3 }^{2} - {2 \sqrt{2} }^{2} } = \frac{3 + 2 \sqrt{2} }{1} = 3 + 2 \sqrt{2}$

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