Question

rationalise 1/root3-root2+1​

Answer 1

Answer:

find the value of 1%2F%28sqrt%283%29-sqrt%282%29-1%29

correct up to 3 decimals if sqrt%282%29=1.414 and sqrt%286%29=2.45

We know the square root of 3 = square root of 6/ sqrt of 2

therefore

1%2F%282.45%2F1.414%29-1.414-1%29 = 1%2F%281.73267-1.414-1%29 = 1%2F%28-.681%29 = -1.468