Rationalise 1 upon underroot 3+ underroot 2
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hey mate .... here's your answer
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Step-by-step explanation:
1/√3+√2
=1/√3+√2*√3-√2/√3-√2
=√3-√2/(√3+√2)(√3-√2)
=√3-√2/{(√3)^-(√2)^}
=√3-√2/1
=√3-√2.
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