Question

rationalise 12/root2+root3+root5

Answer 1

Answer:

hey mate here is your answer

Step-by-step explanation:

This is a very good question!

If it were simply 1√a+√b, we would use the conjugate,

and we would multiply by √a−√b√a−√b.

Let's try something like that and see if it works. (This is what we do with problems of kinds we have not seen before. Try something and see if it works.)

1√2+√3+√5=1√2+(√3+√5)

=1[√2+(√3+√5)][√2−(√3+√5)][√2−(√3+√5)]

=[√2−(√3+√5)][√2+(√3+√5)][√2−(√3+√5