Question

rationalise 2/(3-2√2)​

Answer 1

$\huge\bold\parrot{Heya❤️}$

Refer to the attachment ❤️

Answer 2

To rationalize 2/3-√2

Multiply the numerator and denominator by the additive inverse of 3-√2

ie, 3+√2

2/3-√2

=2/3-√2×3+√2/3+√2

=2(3+√2)/(3-√2)(3+√2)

=6+2√2/(3^2-√2^2)

The denominator was of the form (a+b)(a-b)=a^2-b^2

=6+2√2/6-2 Since in (√2)^2 root and square get cancelled =2

=6+2√2/4

Therefore the answer is 6+2√2/4

Hope it helps u..!!!!...