Question

rationalise: 3-2√5 /3+2√5
(three minus two root over five by three plus two root over five) find ???
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Answer 1

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$\frac{3 -2 \sqrt{5} }{3 + 2 \sqrt{5} }$

$\frac{3 - 2 \sqrt{5} }{3 + 2 \sqrt{5} } \times \frac{3 - 2 \sqrt{5} }{3 - 2 \sqrt{5} }$

$= \frac{9 + 4(5)}{9 - 4(5)} = \frac{9 + 20}{9 - 20} = \frac{29}{11}$

$\bold \red{hope \: this \: helps \: you}$