Math, asked by sarwara6570, 2 months ago

rationalise 7+√5
--------
7-√5​

Answers

Answered by prasmita2611
1

Answer:

27 - 7√5/22

Step-by-step explanation:

7-√5/7+√5

Rationalizing the denominator by multiplying both the numerator and the denominator by the reciprocal of the denominator :

= 7-√5/7+√5 x 7-√5/7-√5

= 7-√5)^2/(7)^2 - (√5)^2

Now, at the numerator,

As we know,

(a-b)^2

=a^2 - 2ab + b^2

And,

At the denominator,

As we know,

(a+b)(a-b)

= a^2 - b^2

Therefore,

7-√5)^2/(7)^2 - (√5)^2

= (7)^2-2(7)(√5)+(√5)^2/49-5

= 49 - 14√5 + 5/44

= 49+5 - 14√5/44

=54 - 14√5/44

= 2(27-7√5)/44

= 27 - 7√5/22

HOPE THIS ANSWER WILL HELP YOU.

Similar questions