rationalise. a) 3√2+1/2√5-3
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=3√2+1/2√5-3
=3√2+√5+3/(√5-3)(√5+3)
=3√2+√5+3/5-3
=3√2+√5+3/2
=(6√2+√5+3)/2
=3√2+√5+3/(√5-3)(√5+3)
=3√2+√5+3/5-3
=3√2+√5+3/2
=(6√2+√5+3)/2
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first , we have to rationalise 2√5 - 3 ....... so we will multiply them by changing their sign in nunerator and denominator .......and then solve it...
3√2+1×2√5+3 in whole multiplying but you give the sign of plus
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