Math, asked by drrajeevvij, 1 year ago

Rationalise root 3+1/ 2root -root 3

Please answer fast and correct to be marked brainliest

Answers

Answered by aroojzahoor605
0

 \sqrt{3 }  + 1 \div  \sqrt{2}  -  \sqrt{3}

( \sqrt{3}  + 1)( \sqrt{2}  +  \sqrt{3} ) =  \sqrt{6}  + 3 +  \sqrt{2}  +  \sqrt{3}

( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  +  \sqrt{3} ) = 2 - 3 =  - 1

√6+√3+√2+3

_______________ = -√6-√3-√2-3

-1

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