Rationalise the denominatar:1/root3-root2+1
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1/√3-√2+1.
LET(√3-√2)IS. A
ATQ,
1/A+1. ×. A-1/A-1
A-1 /A square -1
put,
(√3-√2)-1. /. 3+2-2√2-1
√3-√2-1. /. 4-2√2
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