Rationalise the denomination of 5/√3-√5
Answers
Answer:
Given : 5/(√3-√5)
To Find : Rationalize the denominator
Solution:
\dfrac{5}{\sqrt{3} -\sqrt{5} }
3
−
5
5
Rationalize the denominator
=\dfrac{5}{\sqrt{3} -\sqrt{5} } \times \dfrac{\sqrt{3} +\sqrt{5} }{\sqrt{3} +\sqrt{5} }=
3
−
5
5
×
3
+
5
3
+
5
apply Distributive property and use (a + b)(a - b) = a² - b²
= \dfrac{5\sqrt{3} +5\sqrt{5} }{(\sqrt{3})^2 -(\sqrt{5})^2 }=
(
3
)
2
−(
5
)
2
5
3
+5
5
(√a)² = a
= \dfrac{5\sqrt{3} +5\sqrt{5} }{3 -5 }=
3−5
5
3
+5
5
= \dfrac{5\sqrt{3} +5\sqrt{5} }{-2 }=
−2
5
3
+5
5
= -\dfrac{5\sqrt{3}}{2 }- \dfrac{ 5\sqrt{5} }{2 }=−
2
5
3
−
2
5
5
= -\dfrac{5 }{2 }\left( \sqrt{3} + \sqrt{5}\right)=−
2
5
(
3
+
5
)
\dfrac{5}{\sqrt{3} -\sqrt{5} }
3
−
5
5
= -\dfrac{5 }{2 }\left( \sqrt{3} + \sqrt{5}\right)=−
2
5
(
3
+
5
)
Learn More:
Rationalise the denominator of 22/2+√3+√5 - Brainly.in
https://brainly.in/question/1203331
rationalise the denominator of 1/root 5+root6-root2 - Brainly.in
https://brainly.in/question/3740134
rationalise the denominator of 4/2+√3+√7 - Brainly.in
https://brainly.in/question/5297358
Step-by-step explanation:
Hope it helps
# Anime lover
Answer:
what happend
you are not replying me